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/math/ - Mathematics

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File: 10FA814D-3F99-493D-B028-3E94484555B6.png ( 225.41 KB , 712x2584 , 1640980402330.png )

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  No. 91
Reply
>>185 >>701
You can solve this, right?
2 posts and 2 image replies omitted. Click here to view.
>>
  No. 117
no
>>
  No. 185
>>91
Yes. What's the time limit?
>>
  No. 700 >>703
Where is this an Enterance Exam to? I do not think I could do it. My undergraduate univeristy is all multiple choice and so I am nearly finished it having barely written a proof. It's awful.
>>
  No. 701
>>91
sneed
>>
  No. 703
>>700
I somewhat doubt it is an actual entrance exam. It reminds me of 1st year graduate course of mathematical methods in theoretical physics given that it has a bunch of maths without too much coherence.

Also, I think the ban on electronic calculators is quite futile here.

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  No. 257
Reply
>>258 >>452 >>335
no eureka for today, gentlemen
11 posts omitted. Click here to view.
>>
  No. 648 >>649
>>641
Because I love reinventing the wheel
>>
  No. 649 >>650
>>648
Emoji Image you are started from solution when you wrote
x=sqrt[3]p+q+sqrt[3]p−q x=sqrt[3]{p+q}+sqrt[3]{p-q}

If you reinvente the wheel how do you solve
x5+px2+qx+t=0 x^5+px^2+qx+t=0
or
x6+ax3+bx2+cx+d=0 x^6+ax^3+bx^2+cx+d=0
? Emoji Image
>>
  No. 650 >>651
>>649
Me again, edit: when you wrote
x=p+q3+p−q3 x=\sqrt[3]{p+q}+\sqrt[3]{p-q}
sorry for the mistakes Emoji Image
>>
  No. 651
>>650
I said that I guessed it. I kinda remembered the outlook of the original solution with the sum of two cubic roots, but I didn't remember what was inside.
>>
  No. 702
AAAAAAAAA

File: mandlbaur.png ( 24.39 KB , 581x222 , 1713090670790.png )

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  No. 691
Reply
>>692
Evaluate

You should be able to solve this
>>
  No. 692
>>691
Why that humonguous integral though?

File: unknown.png ( 2.62 MB , 2048x2048 , 1650489546718.png )

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  No. 163
Reply
>>475 >>479 >>682
What the fuck is a Polynomial and how do I solve one?
8 posts and 1 image reply omitted. Click here to view.
>>
  No. 479 >>494
>>163
I once knew how to solve polynomials but nowadays anything above degree 2 polynomials is too difficult to me
>>
  No. 494
>>479
Me too, I solve 2-degree equation like this:
x2+ax+b=0x=p+iq x^2+ax+b=0\\ x=p+iq

where
i2=−1i^2=-1

(p+iq)2+a(p+iq)+b=0{p2−q2+ap+b=02iqp+aiq=0{q=±a24+aa2+bp=−a2 \\(p+iq)^2+a(p+iq)+b=0\\ \begin{cases} p^2-q^2+ap+b=0\\ 2iqp+aiq=0 \end{cases} \\ \begin{cases} q=\pm \sqrt{\frac{a^2}{4}+a\frac{a}{2}+b} \\p=-\frac{a}{2} \end{cases}

because i don't remember formula.
>>
  No. 681
waow
>>
  No. 682 >>683
>>163
A poly is the sum of plus mono, until quartic eq. there are the formulas; from 5-degree eq. on... there is a general process, that is still secret
>>
  No. 683
>>682
Test

File: God Wei.JPG ( 35.86 KB , 1098x732 , 1703420790112.jpg )

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  No. 559
Reply
>>669 >>675 >>607 >>629
https://newsen.pku.edu.cn/PKUmedia/11888.html

>Of these 24 questions, Wei Dongyi completed 23 and a half, a record that even his coach was amazed by. He often solved all the questions in the first hour of the test. Many of the methods he used were self-invented and were much more concise than the standard processes, and became known as the "Wei Method".

>
In this competition, Wei beat the legendary Tao Zhexuan, who taught himself calculus at the age of seven and won the IMO gold medal at the age of 12, by a time ratio of 1:7. Tao Zhexuan was invited to solve the sixth problem of the finale, which took him seven hours, while Wei Dongyi took only one hour in the competition.

Is it really impossible to be like him with just learning and studying more? Is it really over, is only option actually suicide? Please be brutally honest, I don't want any false hope.(Even though I know the answer)
15 posts and 2 image replies omitted. Click here to view.
>>
  No. 670 >>671
>>669
I don't think he speaks English and I don't have any addresses.
>>
  No. 671 >>672
>>670
he's an academic, and not some local fauna biologist or *mother tongue* linguist who can get away with only publishing in his native langage, he must speak english and clearly knows enough to have an h-index of 15.

https://www.math.pku.edu.cn/puremath_en/people/faculty/index2.htm
https://www.researchgate.net/profile/Wei-Ab
>>
  No. 672
>>671
Thank you anon.
>>
  No. 674
>>611
intelligence boils down to nothing more than the speed at which you're able to use your brain to accomplish something. or perhaps your argument is that intelligence is largely uncorrelated with math?
>>
  No. 675
>>559
its experience, solve more problems & learn more methods & you'll get better.
even if you don't its not the end of the world. you can still fuck women without being a three time IMO winner.

  No. 136
Reply
>>137 >>173 >>667 >>371 >>372 >>403 >>414 >>448 >>474 >>550
Is thrembo real? It's an integer between 6 and 7.
37 posts and 4 image replies omitted. Click here to view.
>>
  No. 550 >>668
>>136
erm
>>
  No. 667
>>136
Ok
>>
  No. 668
>>550
Hi birb
>>
  No. 676 >>677
>>
  No. 677

File: e9a.png ( 254.35 KB , 680x670 , 1710785235395.png )

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File: IMG_0620.png ( 121.51 KB , 1920x1840 , 1710510012263.png )

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  No. 673
Reply
Hey dudes, can you help me? I would like to reprove Alan Sokal's theorem in another way, I know how to calculate the roots of a chromatic polynomial, but there is a piece missing from my puzzle: how is n-degree a chromatic polynomial calculated?
Pic's chromatic polynomial has degree 10 but it has three obviusly roots: 0,1,2; and it is not hard to calculate septic eq.

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  No. 107
Reply
>>169
Talk maths.
7 posts and 1 image reply omitted. Click here to view.
>>
  No. 170
>>169
For discussion not specific to any single topic
>>
  No. 563 >>657
>>132
Area as in its Hausdorff dimension dimensional Hausdorff measure? Or Lebesgue measure of its convex hull?
>>
  No. 566
>>112
same
>>
  No. 657 >>658

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>>132
>>563
Wouldn't it be an improper integral over the complex plane?
>>
  No. 658
>>657
https://mathoverflow.net/questions/453862/is-the-area-of-the-mandelbrot-set-known

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  No. 661
Reply
What do you guys think about competitive national exams like CSAT, Gaokao, JEE and more?

File: 62f2b3b7b7b09276a4ad01f2_Unit Circle Degrees.gif ( 58.82 KB , 1024x1024 , 1680066461904.gif )

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  No. 366
Reply
>>622 >>623 >>625 >>656
what's the most important trig concept you remember?
5 posts and 2 image replies omitted. Click here to view.
>>
  No. 623 >>624
>>366
That the squares of sine and cosine sum to 1. Or rather that R[sin,cos] is but R[x,y]/(1-x^2-y^2).
>>
  No. 624 >>654
>>623
True, because that equation creates the whole unit circle.

>>367
Moduloing by m partitions the number line into m partitions. 6, being 1m + 1, is equivalent to 11 because it's 2m + 1. Your number of cycles would be the multiplier of m.
>>
  No. 625

File: aed06f9a626ed4a0dfa92e186c44f458.png ( 1.58 MB , 868x1228 , 1705903015096.png )

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>>366
Writing sin and cos in terms of exponentials has served me quite well in complex analysis lol :)
>>
  No. 654
>>624
Well, but actually 11 is in base 5 and not in base 10 in fact you wrote 6 in base 10, being 1m+1 that have an extra turn that it is not counted, why?
>>
  No. 656
>>366
pythagoras

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