Behold, the \textbf{Barnett-Tooker-Wildberger conjecture}.

Let

,,\qquad \hat\zeta_b(s) = \sum_{k=1}^{\hat\infty - b} n^{-s}

then

,,\qquad \hat\zeta_{e + \pi + \sqrt 2}(-1) = \frac{e^{i\pi}}{11 + 0.999\dots}